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Introduction
Abbreviations used:
| A. Absorbance = Optical Density (O.D.) |
SRBC = Sheep Red Blood Cells |
| Conc. = Concentration |
PBS = Phosphate buffered saline |
| l (lambda) Wavelength |
TT = Test Tube |
| d= H2O Distilled water |
Hgb= Hemoglobin |
In biology, it is frequently useful to prepare serial
dilutions. For example, you may want to test the biological
activity of a hormone over a range of concentrations and making
a serial dilution is a quick, easy and accurate way to prepare
these solutions. In this exercise you will test and practice your
ability to pipette accurately by making a series of dilutions
of a colored solution. The intensity of the color in each of the
dilutions will serve as a measure of the precision of your pipetting.
The source of the colored solution will be the hemoglobin contained
in sheep red blood cells. The following suggestions will be helpful
in developing good techniques:
1. Wipe the tip of the pipette with paper tissue to remove fluid
adhering to the outside surface.
2. Pipettes should be held vertically and at eye level because
pipettes are calibrated to be held vertically and read most accurately
in this position.
Materials for dilutions using serological pipettes per table:
| 10% SRBC in PBS: 1+ mL per group |
d H2O: 50 ml |
| 15 x 125 mm TT (16 ml capacity): 8 |
5 or 10 ml pipettes: 6 |
| 1 ml pipette: 6 |
Kimwipes |
| Parafilm to cover 15 x 125 mm TTs |
Scissors to cut parafilm |
| TT rack for 15 x 125 mm TT: 1 |
Container for dirty pipettes |
| Wax glass marking pencil |
25 or 50 mL graduated cylinder |
| Unknown hemoglobin solution in PBS, somewhere between 0.3%
- 10%: 5 ml |
Spectrophotometer (2 per lab) |
Dilution procedure using serological pipettes.
The concentration of red blood cells (RBC) in a suspension can
be accurately determined by photometrically measuring their hemoglobin
content. To release the hemoglobin from the cells so that it can
be measured, the cells are lysed by hypotonic shock (e.g., putting
them into distilled water). The hemoglobin molecule has a characteristic
red color in solution and absorbs visible radiation strongly at
541 nm. In order to assure that all RBCs lyse it is important
that they be diluted in a large amount of hypotonic solution.
We will use a 15x dilution of the SRBC (i.e., 1.0 ml of the 10%
SRBC into 14.0 ml distilled H2O in tube 1. After mixing well and
allowing a couple of minutes for SRBC to lyse, two-fold dilutions
are made for tubes 2 through 7.
Before starting the exercise, practice your pipetting technique
by seeing how accurately you can measure distilled water. Using
the 5 mL pipet, transfer 13 mL of water to a graduated
cylinderand then read the volume of water using the gradations
marked on the cylinder. If you are off by more than 1/2 mL, you
need more practice before beginning the exercise! All members
of the group should become comfortable with the pipets as you
will be required to use them in the future.
Procedure: Prepare the following solutions. Detailed instructions
are below the table.
TT |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
Hgb (mL) |
1.0 |
5.0 |
5.0 |
5.0 |
5.0 |
5.0 |
5.0 |
H20 |
14.0 |
5.0 |
5.0 |
5.0 |
5.0 |
5.0 |
5.0 |
Dilution |
|
1/2 |
1/4 |
1/8 |
1/16 |
1/32 |
1/64 |
SRBC Conc.(%) |
10 |
5 |
2.5 |
1.25 |
0.63 |
0.32 |
0.16 |
1. Pipet 14 ml dH2O in TT #1 and add 1.0 ml of 10% SRBC to this.
Cover with parafilm and mix well by inverting 5 times. (In TT
#1 hemoglobin is considered undiluted because all subsequent calculations
are made relative to that sample.)
2. Pipet 5.0 ml of dH2O into each of 6 TTs.
3. Transfer 5 ml of #1 to TT #2 containing 5.0 ml of dH2O. Mix
as before (= 1/2 dilution).
4. Repeat the above process to obtain 1/4, 1/8, 1/16, 1/32, and
1/64 dilutions.
5. Place solutions in a cuvette, starting from 1/64 dilution,
and read absorbance (O.D.) values at 541 nm.
6. You will obtain a hemoglobin solution of unknown concentration
from your instructor.
Determine its O.D. at 541 nm.
Results:
a. Prepare a graph
showing O.D.541 vs. relative hemoglobin concentration.
b. Determine the relative hemoglobin concentration of the unknown
sample.
Question:
Why not measure the darker colored solutions before the lighter
colored ones?
Some Notes on Graphing
We will be doing a significant amount of graphingin
this laboratory and it is very important that you do it correctly.
It is even more important that you be able to look at graphs in
the literature and really understand what they mean. Having some
practice with making your own graphs will make interpretation
of literature data much simpler. Here are some rule to follow
while preparing your graphs. Most important rule of all. All graphs
must be done neatly, with the X and Y axis clearly labeled using
the proper units.
Other important rules.
1. Always graph absorbance on the Y axis, concentration on the
X axis.
2. Make sure you position the concentration numbers to be linear
on your graph.
3. Always have the lowest concentration on the left side of the
graph. Frequently, but not always, the origin will be zero. Likewise,
when graphing O.D., start with the smallest number at the bottom
of the graph.
4. Use as much of the graph paper as possible while still keeping
the graph accurate. Tiny graphs using just a small corner of the
paper are unacceptable. Your instructors eyes are getting old
and need all the help they can get.
5. It is often very useful to generate a standard curve to be
used when calculating the concentration of an unknown. In a standard
curve, the absorbance of a series of solutions with known concentrations
are determined The absorbance values are plotted on a graph and
the standard curve drawn. When you are making a standard curve
using absorbance values, always draw your best fit straight line
between the data points. DO NOT connect all the data points if
they are not directly on this line. Your best fit line is an average
of all the data points, and thus is a more accurate representation
of absorbance vs. concentration than any single data point.
Determining the concentration of unknown solutions. We commonly
use graphs to determine the concentration of unknowns. In these
types of problems, you will be given a standard and will make
serial dilutions. Reading the absorbance of these standard solutions
will allow you to make your standard curve (using the instructions
above) and then determine the concentration of your unknown. We
will use the plot and drop method with the following steps:
1. Determine the absorbance of the unknown solution.
2. Draw a straight line from the absorbance value on the graph
until it intersects with the standard curve. This is your plot.
3. Drop a straight line from the point of intersection to the
X axis and read the concentration off the graph.
4. When determining the actual concentration of the unknown, remember
to multiply by any dilution factors used while preparing the unknown.
Serial Dilution Problems.
Work these problems BEFORE leaving class today.
Be forewarned: you will see this kind of problem again!
We commonly use multiple dilutions of a single sample in procedures
for estimating concentrations of serum proteins. Frequently, these
will be very high dilutions, making it necessary to use serial
dilutions for minimizing the use of excess reagents and in order
to work with appropriate volumes. Also, we may need to run experiments
on each of the dilutions to see which has a desired effect or
to make a standard curve like we did in today’s exercise.
Often, we will do these dilutions as serial dilutions, which are
a series of equal small dilutions used to obtain a large final
dilution. For example, we might want to do 5 serial two-fold dilutions.
We could do this by adding 1 mL of solute to 1 mL of solvent,
mixing, transferring 1 mL of this mixture to another mL of solvent,
mixing, transferring to 1 mL of solvent and so on. The dilution
would be 1/2 in the first tube, 1/4 in the second, then 1/8, 1/16
and finally 1/32 in the final tube. This final tube would have
a dilution factor (the inverse of the ratio) of 32. Likewise,
we could perform serial 5-fold dilutions by transferring 1 mL
of solute into 4 mL of solvent . The dilutions for 5 of these
steps would be 1/5, 1/25, 1/125, 1/625 and 1/3125, for a dilution
factor of 3,125. You can see the savings in solvent clearly in
the latter example as only 25 mL of solvent was necessary to prepare
this 3,000+-fold dilution.
1. Starting with 1 ml of an undiluted solution, perform the serial
dilutions shown below. Calculate the dilution at each step. What
is the final dilution factor?
2. Perform a series of 6, 5-fold dilutions. What is the final
dilution? You may find it helpful to actually sketch the test
tubes as was done for you in problem 1.
3. If you performed four 2-fold dilutions and the final concentration
was 1.5%, what was the initial concentration? 1 point
4. What is the final dilution of the following?
5. If you begin with a 1/10 dilution and do 5 more 2-fold dilutions,
what is the final dilution?
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